COMO FAZER ALMOFADA...

Method of calculating material

need for Canadian smocking for

"Matrix design"

 

 

 This design contains repetition of 2 columns

of squares marked with diagonals

(shown in pink colour) and one column

which is left blank (Shown in green colour). 

Finally ends with 2 columns of squares 

marked with diagonals.Tthat means there 

should be odd numbers of columns marked

with diagonals  separated by Gaps. In other 

words first and last columns should be

columns marked with diagonals. Numbers 

of repetitions of these three columns 

depend upon the size of the cushion 

and the size of the square of the graph used.
Smocking is done on pairs of columns marked

with diagonals together. After completing one

pair of column we have to move on to the next pair.


Width of the material after smocking

After smocking the width of one pair of 

column of squares become equal to ½ if the 

diagonal of the square used.he gap takes

the shape of an equilateral triangle 

(See the diagram 1) whose side is equal 

to the diagonal of the square. Width 

of the gap will be equal to the height 

of the triangle thus formed.
Height of the triangle can be calculated 

by using the diagonal of the square used
Height of the triangle =√ (diagonal²–½diagonal²) .

No need to worry about the formula. I have given

the table which gives the diagonal and height 

of the triangle formed when smocking is 

done on different sizes of squares.

Length

After smocking the height of two

rows will be equal to the 

diagonal of the square
With the help of these calculations

we can find out the number of squares we

need in each row and in each column. And 

then the material needed..Figures3,4and 5

explain the changes that take place after

smocking for different sizes of squares

I will give one example
How to calculate material needed for a 

cushion of size 40cm x40cm smocking

done on graph with squares 3cm x 3cm
Width
After smocking width first column

becomes half of the diagonal =2.1cm
Width of next gap will be equal to 

height of the triangle formed = 3.6cm
Total of these three squares will be 5.7cm
These three squares are repeated
Last column is column of squares with

diagonals (marked pink) its width is 2.1cm
Subtract 2.1 cm from 40 cm =37.9 cm
Now we have to find out how many

times the fist 3 squares whose width will 

be 5.7 can be repeated to get to get 37.9cm
37.9cm÷ 5.7= 6.6
We can repeat 6 times without fraction 

that means we have to repeat 3 squares 6 times
3x6= 18 squares + last column 2 squares. = 20 squares
If you smock on 20 squares resulting

material will be (8x 5.7) + 2.1= 34.2 cm

+ 2.1cm= 36.3 cm
It is 37  cm approximately  or 4cm less

than 40 cm this can be made up by adding

2 cm on either side as border to this

add 1cm on either side for seams
Length

We get 4, 2 cm when we smock 2 rows
These two rows should be repeated

40 ÷ 4.2= 9.5 times or 9 times 

without taking decimal
2 rows X 9 = 18 rows. When we smock 

these 18 rows the length we

get = 4.2 x 9= 37.8 cm
It is 2.2 cm less than 40 cm. it can 

be made up by adding 1 .1 cm 

on either side. 

To this add 1 cm on either side as border.
So the graph will have 18 rows each row having 20 squares
Width of the material=20 squares x 3cm=60cm + 6cm=66cm
Length of the material = 18 X 3 cm =54 cm + 4.2 cm=56.2 cm
Material needed =66 cm Χ 56.2 cm

 

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